Attenuation (dB) |
R1 (ohm) |
R2 (ohm) |
Standard R1 |
Standard R2 |
3 |
292 |
17,61 |
300 |
18 |
6 |
150 |
37,28 |
150 |
39 |
10 |
96 |
71,15 |
100 |
75 |
20 |
61 |
247,5 |
62 |
240 |
figure 2. - Resistor values for a 50 ohm pi
attenuator network - equal source and load
Under the columns of "actual" I have included
resistors from the E24 series of resistor values. For most practical purposes
these values will suffice.
If, as I suggest you reviewed the topic decibels
you would know that decibel values add together.
A practical example of a pi
attenuator
Assume we have a 50 ohm amateur transmitter with
an output power of five watts. We want to reduce that power down to 250
milli-watts. This means we must reduce the power by 4.75 watts.
This power reduction MUST be dissipated in our pi
network attenuator. This is a very important point to keep in mind, I will tell
you later as to why.
By simple calculation we know that this is 4.75 /
5.0 = .95 or a 95% reduction in power.
Looked at in another way all we want is 5% of the
original power or 1 /20th. On my calculator 5% is expressed as .05 and log .05 =
1.301 which from our tutorial on decibels we know to multiply by 10 because we
are dealing in power levels. This means we're looking for a power reduction of
13 dB.
Using the formula in figure 1 we will now
construct a 13 dB "pi network attenuator" designed for equal source and load
impedances of 50 ohms.
Calculating a practical
example of a 13 db pi network attenuator
We start by determining our "K" factor for 13
dB.
K = 10 (13 dB / 20)
= 10 (0.65) = 4.4668
Determine R1 where (K + 1) = 4.4668 + 1 = 5.4668
and (K - 1) = 4.4668 - 1 = 3.4668 and (K + 1) / (K -1) = 5.4668 / 3.4668 =
1.5769
As you can see these mathematics are "real" hard.
We multiply this answer 1.5769 by our impedance "Z" which is, 1.5769 X 50 =
78.84 ohms for R1. This is depicted in figure 3 below
figure 3. - A practical example of a pi
attenuator at work
Now we calculate R2 and again our "K" value for a
13 dB attenuator remains at 4.4668
First we take the square of "K" which of course
is 19.95, subtract 1 = 18.95, then divide by "K". This becomes 18.95 / 4.4668 =
4.24
This figure is then multiplied by our impedance
"Z" which has been divided by two. In our case we get 4.24 X (50 / 2) = 106
ohms. Now could I make anything simpler to follow?
Calculating unequal
impedance pi-attenuators
A more generic topology of a pi-attenuator is shown
below
The related formulas to calculate the three resistors are more
complex with respect to the same topology but with equal impedance, in this case
they are
where:
Zin = desired
input resistance (ohm)
Zout = desired output resistance
(ohm)
A = transducer loss (dB)
Minimum loss that can be achieved for given Zin and
Zout
T network attenuator
This attenuator network is somewhat different with respect to the
previous pi type. Notice the different but somewhat similar calculations.
Anyway, I've sometimes used this topology, and beyond
that.
figure 4. - "T" network attenuator
For me the calculations are no more difficult or easier than the pi
network attenuator. Anyway I have included a small table below which depicts
common power reduction values of a “T” attenuator of 3 db, 6 dB, 10 dB and 20
dB. Please refer to figure 4 schematic.
Attenuation (dB) |
R1 and R2 (ohm) |
R3 (ohm) |
Std R1 and R2 |
Std R3 |
3 |
8,5 |
141,9 |
8,2 |
150 |
6 |
16,6 |
66,9 |
16 |
68 |
10 |
25,9 |
35,1 |
24 |
36 |
20 |
40,9 |
10,1 |
43 |
10 |
Calculating unequal impedance
T-attenuators
A more generic topology of a T-attenuator is shown
below
The related formulas are shown
below:
where:
Zin = desired
input resistance (ohm)
Zout = desired output resistance
(ohm)
A = transducer loss (dB)
Minimum loss that can be achieved for given Zin and
Zout
Summarising attenuators
1.
Complete your calculations of resistor values in a methodical manner
and double check them.
2.
Do take power dissipation into account. Allow a good safety margin.
3.
Use non-inductive resistors for RF
applications
4.
If sufficient demand exists I will present a paper on designing
attenuators for unequal terminations.
5.
We discussed the "pi" and "T" type attenuators here. Among others,
there are the "H", "L", "O" and "U", bridge types, balanced and unbalanced
types, ladder types and even attenuators using potentiometers
(audio).
The bridged-T
attenuator
The bridged-T topology is frequently used with PIN diode electronically
controlled attenuators, as shown in figures 5, because only two diodes need to
be controlled (as opposed to three with the T-circuit or pi-circuit
configuration). Variable attenuators using PIN diodes can be designed to have
less intercept-point variation with attenuation setting than a functionally
comparable transistor automatic gain control (AGC) stage
figure 5. – Variable attenuator using PIN diodes
A schematic example of a FM power attenuator is available by clicking
HERE
A schematic example of an UHF overdrive limiter is available by
clicking HERE
figure 6. – Bridged “T” topology
To calculate the Bridged “T” network a set of more simple formulas can be
used, they are reported below (please refer to figure 6)
Bridged T component values:
where:
A = desired attenuation loss (dB)
Z0 =
terminating system impedance (ohm)
That's all, enjoy for it!!
;-)
Carlo